Given three integers a b and c where c can be either 0 or 1. Without using any arithmetic relational and conditional operators set the value of a variable x based on below rules - If c = 0 x = a Else // Note c is binary x = b.
Examples: Input: a = 5 b = 10 c = 0; Output: x = 5 Input: a = 5 b = 10 c = 1; Output: x = 10
Lösning 1: Using arithmetic operators If we are allowed to use arithmetic operators we can easily calculate x by using any one of below expressions - x = ((1 - c) * a) + (c * b) OR x = (a + b) - (!c * b) - (c * a); OR x = (a * !c) | (b * c);
CPP #include using namespace std; int calculate(int a int b int c) { return ((1 - c) * a) + (c * b); } int main() { int a = 5 b = 10 c = 0; int x = calculate(a b c); cout << x << endl; return 0; }
5
Lösning 2: Without using arithmetic operators The idea is to construct an array of size 2 such that index 0 of the array stores value of variable 'a' and index 1 value of variable b. Now we return value at index 0 or at index 1 of the array based on value of variable c. CPP #include using namespace std; int calculate(int a int b int c) { int arr[] = {a b}; return *(arr + c); } int main() { int a = 5 b = 10 c = 1; int x = calculate(a b c); cout << x << endl; return 0; }
10
