Med tanke på en rektangulär matris kan vi flytta från nuvarande cell i fyra riktningar med lika sannolikhet. De fyra riktningarna är höger vänster eller botten. Beräkna sannolikheten för att efter N flyttar från en given position (i J) i matrisen kommer vi inte att korsa gränserna för matrisen vid någon tidpunkt.
javascript rullgardinsmeny
Vi rekommenderar dig starkt att minimera din webbläsare och prova detta själv först.
Tanken är att utföra något liknande DFS. Vi korsar rekursivt i var och en av de fyra tillåtna riktningen och för varje cell som möter beräknar vi den nödvändiga sannolikheten med en mindre rörelse. Eftersom varje riktning har lika sannolikhet kommer varje riktning att bidra till 1/4 av den totala sannolikheten för den cellen, dvs. 0,25. Vi returnerar 0 om vi går utanför matrisen och returnerar 1 om N -steg är klar utan att korsa matrisgränser.
Nedan är implementeringen av ovanstående idé:
C++/// C++ program to find the probability // that we do not cross boundary of a // matrix after N moves. #include
/// C program to find the probability // that we do not cross boundary of a // matrix after N moves. #include
// Java program to find the probability // that we do not cross boundary // of a matrix after N moves. import java.io.*; class GFG { // check if (x y) is valid // matrix coordinate static boolean isSafe(int x int y int m int n) { return (x >= 0 && x < m && y >= 0 && y < n); } // Function to calculate probability // that after N moves from a given // position (x y) in m x n matrix // boundaries of the matrix will // not be crossed. static double findProbability(int m int n int x int y int N) { // boundary crossed if (! isSafe(x y m n)) return 0.0; // N steps taken if (N == 0) return 1.0; // Initialize result double prob = 0.0; // move up prob += findProbability(m n x - 1 y N - 1) * 0.25; // move right prob += findProbability(m n x y + 1 N - 1) * 0.25; // move down prob += findProbability(m n x + 1 y N - 1) * 0.25; // move left prob += findProbability(m n x y - 1 N - 1) * 0.25; return prob; } // Driver code public static void main (String[] args) { // matrix size int m = 5 n = 5; // coordinates of starting point int i = 1 j = 1; // Number of steps int N = 2; System.out.println('Probability is ' + findProbability(m n i j N)); } } // This code is contributed by KRV.
# Python3 program to find the probability # that we do not cross boundary of a # matrix after N moves. # check if (x y) is valid matrix coordinate def isSafe(x y m n): return (x >= 0 and x < m and y >= 0 and y < n) # Function to calculate probability # that after N moves from a given # position (x y) in m x n matrix # boundaries of the matrix will # not be crossed. def findProbability(m n x y N): # boundary crossed if (not isSafe(x y m n)): return 0.0 # N steps taken if (N == 0): return 1.0 # Initialize result prob = 0.0 # move up prob += findProbability(m n x - 1 y N - 1) * 0.25 # move right prob += findProbability(m n x y + 1 N - 1) * 0.25 # move down prob += findProbability(m n x + 1 y N - 1) * 0.25 # move left prob += findProbability(m n x y - 1 N - 1) * 0.25 return prob # Driver code if __name__ == '__main__': # matrix size m = 5 n = 5 # coordinates of starting po i = 1 j = 1 # Number of steps N = 2 print('Probability is' findProbability(m n i j N)) # This code is contributed by PranchalK
// C# program to find the probability // that we do not cross boundary // of a matrix after N moves. using System; class GFG { // check if (x y) is valid // matrix coordinate static bool isSafe(int x int y int m int n) { return (x >= 0 && x < m && y >= 0 && y < n); } // Function to calculate probability // that after N moves from a given // position (x y) in m x n matrix // boundaries of the matrix will // not be crossed. static double findProbability(int m int n int x int y int N) { // boundary crossed if (! isSafe(x y m n)) return 0.0; // N steps taken if (N == 0) return 1.0; // Initialize result double prob = 0.0; // move up prob += findProbability(m n x - 1 y N - 1) * 0.25; // move right prob += findProbability(m n x y + 1 N - 1) * 0.25; // move down prob += findProbability(m n x + 1 y N - 1) * 0.25; // move left prob += findProbability(m n x y - 1 N - 1) * 0.25; return prob; } // Driver code public static void Main () { // matrix size int m = 5 n = 5; // coordinates of starting point int i = 1 j = 1; // Number of steps int N = 2; Console.Write('Probability is ' + findProbability(m n i j N)); } } // This code is contributed by nitin mittal.
// PHP program to find the probability // that we do not cross boundary of a // matrix after N moves. // check if (x y) is valid // matrix coordinate function isSafe($x $y $m $n) { return ($x >= 0 && $x < $m && $y >= 0 && $y < $n); } // Function to calculate probability // that after N moves from a given // position (x y) in m x n matrix // boundaries of the matrix will // not be crossed. function findProbability($m $n $x $y $N) { // boundary crossed if (!isSafe($x $y $m $n)) return 0.0; // N steps taken if ($N == 0) return 1.0; // Initialize result $prob = 0.0; // move up $prob += findProbability($m $n $x - 1 $y $N - 1) * 0.25; // move right $prob += findProbability($m $n $x $y + 1 $N - 1) * 0.25; // move down $prob += findProbability($m $n $x + 1 $y $N - 1) * 0.25; // move left $prob += findProbability($m $n $x $y - 1 $N - 1) * 0.25; return $prob; } // Driver code // matrix size $m = 5; $n = 5; // coordinates of starting point $i = 1; $j = 1; // Number of steps $N = 2; echo 'Probability is ' findProbability($m $n $i $j $N); // This code is contributed by nitin mittal. ?> <script> // JavaScript program to find the probability // that we do not cross boundary of a // matrix after N moves. // check if (x y) is valid matrix coordinate function isSafe(x y m n){ return (x >= 0 && x < m && y >= 0 && y < n); } // Function to calculate probability // that after N moves from a given // position (x y) in m x n matrix // boundaries of the matrix will not be crossed. function findProbability( m n x y N){ // boundary crossed if (!isSafe(x y m n)) return 0.0; // N steps taken if (N == 0) return 1.0; // Initialize result let prob = 0.0; // move up prob += findProbability(m n x - 1 y N - 1) * 0.25; // move right prob += findProbability(m n x y + 1 N - 1) * 0.25; // move down prob += findProbability(m n x + 1 y N - 1) * 0.25; // move left prob += findProbability(m n x y - 1 N - 1) * 0.25; return prob; } // Driver code // matrix size let m = 5 n = 5; // coordinates of starting point let i = 1 j = 1; // Number of steps let N = 2; document.write( 'Probability is ' +findProbability(m n i j N)); </script>
Produktion
Probability is 0.875