De sublist() metod för listgränssnitt returnerar en vy av delen av denna lista mellan inkluderande och exklusiva parametrar. Denna metod eliminerar behovet av explicita intervalloperationer.
Nätverks topologi
Syntax
public List subList(int fromIndex, int toIndex)
Parametrar
Parametrarna 'fromIndex' och 'toIndex' representerar underlistans låga och höga slutpunkt.
Lämna tillbaka
Metoden subList() returnerar en vy av det angivna intervallet inom denna lista.
Kastar:
IndexOutOfBoundsException - Det här undantaget ger ett olagligt slutpunktsindexvärde, dvs frånIndexstorlek eller frånIndex > tillIndex.
Exempel 1
import java.util.LinkedList; import java.util.List; public class JavaListSubListExample1 { public static void main(String[] args) { int fromIndex=2; int toIndex=7; List list= new LinkedList(); for (int i=1;i<=10;i++){ 2 7 list.add(i); } system.out.println('list : '+list); it will return the elements present from index to at list.sublist(fromindex,toindex); system.out.println('elements position '+list.sublist(2,7)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> List : [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] Elements from 2 index position to 7 index position : [3, 4, 5, 6, 7] </pre> <h2>Example 2</h2> <pre> import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_2 { public static void main(String[] args) { List list= new LinkedList(); for (char ch='a';chtoIndex it will throw an exception System.out.println('List : '+list.subList(18,12)); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread 'main' java.lang.IllegalArgumentException: fromIndex(18) >toIndex(12) atjava.util.SubList.(AbstractList.java:624) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample2.main(JavaListSubListExample2.java:12) </pre> <h2>Example 3</h2> <pre> import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_3 { public static void main(String[] args) { List list= new LinkedList(); for (char ch='a';ch<='z';ch++){ list.add(ch); } system.out.println('total alphabets : '+list.size()); if fromindex<-1 || toindex< -1 it will throw an exception system.out.println('list '+list.sublist(-1,-1)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread 'main' java.lang.IndexOutOfBoundsException: fromIndex = -1 atjava.util.SubList.(AbstractList.java:620) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample3.main(JavaListSubListExample3.java:13) </pre></='z';ch++){></pre></=10;i++){> Exempel 2
import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_2 { public static void main(String[] args) { List list= new LinkedList(); for (char ch='a';chtoIndex it will throw an exception System.out.println('List : '+list.subList(18,12)); } } Testa det nu Produktion:
Total alphabets : 26 Exception in thread 'main' java.lang.IllegalArgumentException: fromIndex(18) >toIndex(12) atjava.util.SubList.(AbstractList.java:624) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample2.main(JavaListSubListExample2.java:12)
Exempel 3
import java.util.LinkedList; import java.util.List; public class JavaListSubListExample_3 { public static void main(String[] args) { List list= new LinkedList(); for (char ch='a';ch<=\'z\';ch++){ list.add(ch); } system.out.println(\'total alphabets : \'+list.size()); if fromindex<-1 || toindex< -1 it will throw an exception system.out.println(\'list \'+list.sublist(-1,-1)); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Total alphabets : 26 Exception in thread 'main' java.lang.IndexOutOfBoundsException: fromIndex = -1 atjava.util.SubList.(AbstractList.java:620) atjava.util.AbstractList.subList(AbstractList.java:484) at com.javaTpoint.JavaListSubListExample3.main(JavaListSubListExample3.java:13) </pre></=\'z\';ch++){>